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Object Oriented Programming Using C++
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Course Name
BCA (Bachelor of Computer Application)
Subject Code BC0037 (Object Oriented Programming Using C++)
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PART - A
PART - B
PART - C
Subject : Object Oriented Programming Using C++
BC0037 : PART - B
Q. 1 | Consider the following command given at the DOS prompt _ CA> multiply 10 20 30 Here "multiply" is _ i) the name of the function performing multiplication ii) the name of the file containing the program for multiplication |
| A) | i) only |
| B) | ii) only | | C) | Both A) and B) | | D) | None of these | | | | Q. 2 | Which of these is the correct way to accept a sentence of 25 characters maximum, from the user into char str [25] in C ++? |
| A) | scatift"%s", str), |
| B) | cin.getLine (str, 25, '\n'); | | C) | cin.getline (str, '\'n'), | | D) | None of these | | | | Q. 3 | dentify the situations where inline expansion may not work 1) If a loop, a switch or goto exists in functions returning values 2) If a return statement exists, for functions not returning valves 3. If functions contain static varia |
| A) | 1), 2), 3) |
| B) | 2), 3), 4) | | C) | 1), 3), 4) | | D) | 1), 2), 3), 4) | | | | Q. 4 | In the following code segment, locate the errors and correct them this code is written to calculate area of a triangle using the formula A =1/2 * base * height // upto two digits of precision class Shape ( int base, int height) // Line |
| A) | Computation at line 3 will always result in
zero; type-casting is required |
| B) | Line 2 has to be modified to allow compute
to return a real number upto 2 digits of
precision | | C) | Both A) and B) | | D) | There are no errors ; now the function is
required that will call compute ( ) and get the
result | | | | Q. 5 | How would you make use of the class defined in Q.46 above and get-breadth of a triangle computed if base and height are equal to 10 |
| A) | main() f Shapes (10, 10); cout <<
s.compute |
| B) | main shape s1 * s2;
s2 & sl;
s1.getdata //H 10, 10 should be
entered by H user
cout << * s2.compute | | C) | main shape tri;
tri. getdata //Huser
enters 10, 10
cout << tri.compute | | D) | D)None of the above | | | |
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